插入语句时判断是否存在的SQL语句:
insert into appointmen_record( app_type_id, app_time_id, create_user, appointmen_date ) select "2c8f50808c3b49b1a9dda467aea1d475", "f982f0af7db54a87ba8f3ce189a6e66f", "55aaec489ea9458b99c920828c53755a", "2016-06-16" from dual where not exists (select * from appointmen_record where appointmen_date = '2016-06-18')